# Difference between revisions of "Atmosphere"

The atmosphere of a celestial body slows the movement of any object passing through it, a force known as atmospheric drag (or simply drag). An atmosphere also allows for aerodynamic lift. The celestial bodies with atmospheres are the planets Moho, Eve, Kerbin, Duna and Jool, as well as Laythe, a moon of Jool.

Atmospheric pressure diminishes exponentially with increasing altitude. An atmosphere's scale height is the distance over which atmospheric pressure changes as a factor of e, or 2.718. For example, Kerbin's atmosphere has a scale height of 5000 m, meaning the atmospheric pressure at altitude n is 2.718 times greater than the pressure at altitude n + 5000.

Atmospheres vary in temperature. In many cases this has no bearing on gameplay, but Moho's atmosphere is extremely hot, causing engines to overheat easily and ships to self-destruct at high velocities.

Atmosphere allows aerobraking and easier landing. When atmosphere contains oxygen, it allows jet engines to work. However, atmosphere makes taking off from a planet more difficult and increases a stable orbit altitude.

## Drag

In the game, the force of atmospheric drag (FD) is modeled as follows:[1]

${\displaystyle F_{D}=0.5\,\rho \,v^{2}\,m\,d\,A}$

where ρ is the atmospheric density (kg/m3), v is the ship's velocity (m/s), m is the ship's mass (kg), d is the coefficient of drag (dimensionless), and A is the cross-sectional area (m2).

ρ can be derived from atmospheric pressure (p), which in turn is given by a formula on a planet's wiki page:

${\displaystyle \rho =p\cdot 1.2230948554874\cdot 0.008}$

The coefficient of drag (d) is calculated as the mass-weighted average of the max_drag values of all parts on the ship. For most ships without deployed parachutes, d will be very near 0.2, since this is the max_drag value of the vast majority of parts.

Note that the game does not calculate the ship's cross-sectional area (A) and assumes a value of 1 instead. This means the net force of drag on a spacecraft is unaffected by the width or orientation of a spacecraft, even if the spacecraft has very large wings. (Wings do affect the force of lift, however.)

## Terminal velocity

The terminal velocity of an object falling through an atmosphere is the velocity at which the force of gravity is equal to the force of drag. Terminal velocity changes as a function of altitude. Given enough time, an object falling into the atmosphere will slow to terminal velocity and then remain at terminal velocity for the rest of its fall.

Terminal velocity is important because:

1. It describes the amount of velocity which a spacecraft must burn away when it is close to the ground.
2. It represents the speed at which a ship should be traveling upward during a fuel-optimal ascent.

The force of gravity (FG) is:

${\displaystyle F_{G}=m\,a=m\,{\frac {GM}{r^{2}}}}$

where m is still the ship's mass, G is the gravitational constant, M is the mass of the planet, and r is the distance from the center of the planet to the falling object.

To find terminal velocity, we set FG equal to FD:

${\displaystyle m\,{\frac {GM}{r^{2}}}=0.5\,\rho \,v^{2}\,m\,d\,A}$
${\displaystyle {\frac {GM}{r^{2}}}=0.5\,\rho \,v^{2}\,d\,A}$
${\displaystyle v=v_{T}={\sqrt {\frac {2\,GM}{r^{2}\,\rho \,d\,A}}}}$

Assuming d is 0.2 (which is a good approximation, provided parachutes are not in use) and given that A is 1, this simplifies to:

${\displaystyle v_{T}={\sqrt {\frac {10\,GM}{r^{2}\,\rho }}}}$

### Examples

Altitude (m) vT (m/s)
Moho Eve Kerbin Duna Jool Laythe
0 Expression error: Unexpected < operator. 58.385 100.13 212.41 23.124 115.62
100 Expression error: Unexpected < operator. 58.783 101.01 214.21 23.162 116.32
1000 Expression error: Unexpected < operator. 62.494 109.30 231.16 23.508 122.83
10000 Expression error: Unexpected < operator. 115.27 240.52 495.18 27.272 211.77