Difference between revisions of "Thrust-to-weight ratio"

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(-uppercased name (seems random and if somebody can't figure out why it's called TWR, this person won't understand this article); +TWR not important for orbital maneuvers; *rewritten when it is important; *inverted the tilted engine formula;)
(you can also use parachutes on bodies with atmospheres. Also cleaned up the Physical background section)
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[[File:Gravity_turn_start.svg|thumb|The TWR is the ratio of F<sub>T</sub> and F<sub>G</sub>. F is pointing upwards if the TWR > 1, downwards if TWR < 1 or doesn't exist if TWR = 0]]
 
[[File:Gravity_turn_start.svg|thumb|The TWR is the ratio of F<sub>T</sub> and F<sub>G</sub>. F is pointing upwards if the TWR > 1, downwards if TWR < 1 or doesn't exist if TWR = 0]]
The '''thrust-to-weight ratio''' (TWR) is a ratio that defines the power of a craft's engines in relation to its own weight. If a [[craft]] needs to get into a stable [[orbit]] or land safely on the current body, its engines must put out more thrust than its current weight to counteract gravity. In a stable orbit, the thrust-to-weight ratio is not important, but it's value can be used to estimate the maximum acceleration possible. In the terms of a ratio, a craft with a greater thrust than weight will have a TWR greater than 1. The weight depends on the mass and local gravitational acceleration, which is usually the surface gravity of the body the craft is currently in the gravity well of.
+
The '''thrust-to-weight ratio''' (TWR) is a ratio that defines the power of a craft's engines in relation to its own weight. If a [[craft]] needs to get into a stable [[orbit]] or land safely on the current body without using [[parachute]]s, then its engines must put out more thrust than its current weight to counteract gravity. In a stable orbit, the thrust-to-weight ratio is not important, but it's value can be used to estimate the maximum acceleration possible. In the terms of a ratio, a craft with a greater thrust than weight will have a TWR greater than 1. The weight depends on the mass and local gravitational acceleration, which is usually the surface gravity of the body the craft is currently in the gravity well of.
  
 
If the ratio is less than 1 and the craft is on the surface, then the craft won't be able to lift off of the ground. If such a craft is currently falling towards the surface, then the craft's engines won't have enough thrust to slow down for a soft landing.
 
If the ratio is less than 1 and the craft is on the surface, then the craft won't be able to lift off of the ground. If such a craft is currently falling towards the surface, then the craft's engines won't have enough thrust to slow down for a soft landing.
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== Physical background ==
 
== Physical background ==
To lift off, the [[engine]]s need to supply enough force to counteract the gravitational pull. The thrust, meaning the force supplied by the engines, is the sum of the thrust of all running engines. Usually the maximum thrust is used to know the upper limits. The gravitational pull is the weight of the craft which can be calculated by multiplying the mass with the current gravitation. To make the formula easier the surface gravity of the celestial body in question is used.
+
To lift off, the [[engine]]s need to supply enough force in the opposite direction of the gravitational pull to counteract it. The total thrust, or the force supplied by all the engines, is the sum of the thrust of all running engines. Usually the maximum thrust is used to know the upper limits. The gravitational pull is the weight of the craft which can be calculated by multiplying the mass with the current gravitation. To make the formula easier the surface gravity of the celestial body in question is used.
 
:<math>\begin{align}
 
:<math>\begin{align}
 
   \sum\limits_i F_{T_\text{engine i}} = F_T &> F_G = m \cdot g \\
 
   \sum\limits_i F_{T_\text{engine i}} = F_T &> F_G = m \cdot g \\
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\end{align}</math>
 
\end{align}</math>
  
This value isn't constant over a flight for three reasons:
+
This value isn't constant over a flight because of three reasons:
# Because the engines consume [[resource]]s, the rocket gets lighter over time, raising the ratio over time
+
# As the engines consume [[resource]]s, the craft gets lighter over time, raising the ratio
# Because the gravity lowers with a higher altitude, the ratio is proportional to the altitude
+
# The gravitational pull is lower the farther from a body, so the ratio is proportional to the altitude
# Because on certain engines the thrust can be throttled, modified thrust during flight leads to a lower ratio than calculated
+
# On certain engines the thrust can be throttled, so lowering the thrust during flight leads to a lower ratio than one calculated for full throttle
  
 
[[File:Gravity_turn_executed.svg|thumb|The engine is tilted by <math>\alpha = 30^\circ</math>, reducing the TWR]]
 
[[File:Gravity_turn_executed.svg|thumb|The engine is tilted by <math>\alpha = 30^\circ</math>, reducing the TWR]]
As soon as the rocket starts with the [[gravity turn]] only a portion of the craft's thrust is applied to counteract gravity, reducing the TWR. To calculate how much thrust is used to counteract gravity the pitch of the engine can be included:
+
As soon as a craft starts with the [[gravity turn]] only a portion of the craft's thrust is applied to counteract gravity, reducing the TWR. To calculate how much thrust is used to counteract gravity the pitch of the engine can be included:
 
{{Formula|math=F_\mathit{eff} = F_T \cdot \cos(\alpha)|where=* <math>F_\mathit{eff}</math> is the effective thrust to counteract gravity
 
{{Formula|math=F_\mathit{eff} = F_T \cdot \cos(\alpha)|where=* <math>F_\mathit{eff}</math> is the effective thrust to counteract gravity
 
* <math>F_T</math> is the engine's thrust
 
* <math>F_T</math> is the engine's thrust

Revision as of 16:46, 8 October 2013

The TWR is the ratio of FT and FG. F is pointing upwards if the TWR > 1, downwards if TWR < 1 or doesn't exist if TWR = 0

The thrust-to-weight ratio (TWR) is a ratio that defines the power of a craft's engines in relation to its own weight. If a craft needs to get into a stable orbit or land safely on the current body without using parachutes, then its engines must put out more thrust than its current weight to counteract gravity. In a stable orbit, the thrust-to-weight ratio is not important, but it's value can be used to estimate the maximum acceleration possible. In the terms of a ratio, a craft with a greater thrust than weight will have a TWR greater than 1. The weight depends on the mass and local gravitational acceleration, which is usually the surface gravity of the body the craft is currently in the gravity well of.

If the ratio is less than 1 and the craft is on the surface, then the craft won't be able to lift off of the ground. If such a craft is currently falling towards the surface, then the craft's engines won't have enough thrust to slow down for a soft landing.

Formula

Where:
  • is the thrust of the engines
  • the total mass of the craft
  • the local gravitational acceleration (usually surface gravity)

When the TWR and surface gravity for a celestial body (A) is known, it is possible to calculate the TWR for the surface gravity of another celestial body (B). Especially if the known TWR is for Kerbin, it is possible to use the surface gravity given in g-force acting on the second body.

, the gravitational acceleration is given in multiples of (g-force).

To estimate the maximum acceleration () only from knowing the TWR and gravitational acceleration the following formula can be used:

Where:
  • the thrust-to-weight ratio for the given
  • The rest are the same from the original formula

Physical background

To lift off, the engines need to supply enough force in the opposite direction of the gravitational pull to counteract it. The total thrust, or the force supplied by all the engines, is the sum of the thrust of all running engines. Usually the maximum thrust is used to know the upper limits. The gravitational pull is the weight of the craft which can be calculated by multiplying the mass with the current gravitation. To make the formula easier the surface gravity of the celestial body in question is used.

This value isn't constant over a flight because of three reasons:

  1. As the engines consume resources, the craft gets lighter over time, raising the ratio
  2. The gravitational pull is lower the farther from a body, so the ratio is proportional to the altitude
  3. On certain engines the thrust can be throttled, so lowering the thrust during flight leads to a lower ratio than one calculated for full throttle
The engine is tilted by , reducing the TWR

As soon as a craft starts with the gravity turn only a portion of the craft's thrust is applied to counteract gravity, reducing the TWR. To calculate how much thrust is used to counteract gravity the pitch of the engine can be included:

Where:
  • is the effective thrust to counteract gravity
  • is the engine's thrust
  • is the pitch of the engine (0° straight downward, 90° straight sideways)

This can also be used to calculate the thrust for engines that are placed angled on the craft. Technically it is like they are already pitched. Usually the engines on the other side are angled too, to thrust only upwards reducing the efficiency of the engines, because some thrust is cancelled out by them.

Examples

The Kerbal X with a mass of 131.32 t, 6 LV-T45 Liquid Fuel Engines and 1 Rockomax "Mainsail" Liquid Engine on the launch pad of the Kerbal Space Center has a TWR of:

A TWR of 2.096 is above 1 and means liftoff!

The third stage of a Kerbal X with a mass of 16.52 t and the LV-909 Liquid Fuel Engine with 50 kN thrust can not lift off from Kerbin but it can lift off from the Mun:

See also