Difference between revisions of "User talk:XZise/Atmospheric Height"

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(Created page with "“So applying Jool's “atmospheric height pressure” on Kerbin means, that you can savely orbit at about 56 km which is way lower than 69 km.“ In KSP, pressure is discon...")
 
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In KSP, pressure is discontinuous at atmospheric height: when the wiki says that the pressure is 10⁻⁶ atm at atmospheric height, it means that it is 10⁻⁶ atm right below and exactly 0 atm (i.e. no drag simulated) right above. Orbits on Kerbin above 70 km and orbits on Jool above 139 km are stable because pressure is exactly 0 atm.
 
In KSP, pressure is discontinuous at atmospheric height: when the wiki says that the pressure is 10⁻⁶ atm at atmospheric height, it means that it is 10⁻⁶ atm right below and exactly 0 atm (i.e. no drag simulated) right above. Orbits on Kerbin above 70 km and orbits on Jool above 139 km are stable because pressure is exactly 0 atm.
 
  
 
An orbit on Kerbin at altitude 69,077.552 m (1 mm before top of atmosphere) would experience 10⁻⁶ atm while an orbit on Jool at altitude 138,155.10 m would experience 15×10⁻⁶ atm. Both would  eventually decay although it might take a few decades in ×4.
 
An orbit on Kerbin at altitude 69,077.552 m (1 mm before top of atmosphere) would experience 10⁻⁶ atm while an orbit on Jool at altitude 138,155.10 m would experience 15×10⁻⁶ atm. Both would  eventually decay although it might take a few decades in ×4.
  
 
— [[User:Yoha|Yoha]] ([[User talk:Yoha|talk]]) 14:12, 26 December 2014 (CST)
 
— [[User:Yoha|Yoha]] ([[User talk:Yoha|talk]]) 14:12, 26 December 2014 (CST)
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“you know could construct an example with an sea level pressure of 10⁺⁶ atm resulting in a pressure of 1 atm at the “atmospheric height” which is the pressure at Kerbin's sea level.”
 
“you know could construct an example with an sea level pressure of 10⁺⁶ atm resulting in a pressure of 1 atm at the “atmospheric height” which is the pressure at Kerbin's sea level.”

Revision as of 20:13, 26 December 2014

“So applying Jool's “atmospheric height pressure” on Kerbin means, that you can savely orbit at about 56 km which is way lower than 69 km.“

In KSP, pressure is discontinuous at atmospheric height: when the wiki says that the pressure is 10⁻⁶ atm at atmospheric height, it means that it is 10⁻⁶ atm right below and exactly 0 atm (i.e. no drag simulated) right above. Orbits on Kerbin above 70 km and orbits on Jool above 139 km are stable because pressure is exactly 0 atm.

An orbit on Kerbin at altitude 69,077.552 m (1 mm before top of atmosphere) would experience 10⁻⁶ atm while an orbit on Jool at altitude 138,155.10 m would experience 15×10⁻⁶ atm. Both would eventually decay although it might take a few decades in ×4.

Yoha (talk) 14:12, 26 December 2014 (CST)


“you know could construct an example with an sea level pressure of 10⁺⁶ atm resulting in a pressure of 1 atm at the “atmospheric height” which is the pressure at Kerbin's sea level.”

Absolutely, since the threshold is relative the pressure at sea level, a planet could be conceived where the pressure discontinuity would be huge. Using an absolute threshold would make more sense. — Yoha (talk) 14:12, 26 December 2014 (CST)