Difference between revisions of "Talk:Tutorial:Advanced Rocket Design"
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(→Question: 9.81 m/s^2 in delta V calculations?) |
(dammit, why won't the math work??) |
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I'm assuming that the devs used an earth-like parameter for Kerbin, and obviously this math is working for you; but do you use a different acceleration parameter when calculating the delta-V of your Munar return stage? --[[User:Hovissimo|Hovissimo]] ([[User talk:Hovissimo|talk]]) 19:45, 25 December 2012 (UTC)<P><P> | I'm assuming that the devs used an earth-like parameter for Kerbin, and obviously this math is working for you; but do you use a different acceleration parameter when calculating the delta-V of your Munar return stage? --[[User:Hovissimo|Hovissimo]] ([[User talk:Hovissimo|talk]]) 19:45, 25 December 2012 (UTC)<P><P> | ||
No, the 'g' is a standard unit of measurement. Changing it would be like changing the length of a metre because the Mun "has less of them". [[User:Kahlzun|Kahlzun]] ([[User talk:Kahlzun|talk]]) 07:37, 2 January 2013 (UTC) | No, the 'g' is a standard unit of measurement. Changing it would be like changing the length of a metre because the Mun "has less of them". [[User:Kahlzun|Kahlzun]] ([[User talk:Kahlzun|talk]]) 07:37, 2 January 2013 (UTC) | ||
| − | ::Isn't that kind of arbitrary, though? Wouldn't <math>\Delta v = I_{sp}\cdot \ln \left ( \frac{ | + | ::Isn't that kind of arbitrary, though? Wouldn't <math>\Delta v = I_{sp}\cdot \ln\left(\frac{m_1}{m_2}\right)</math> make more sense? |
Revision as of 23:10, 22 March 2013
Question: 9.81 m/s^2 in delta V calculations?
Isn't that figure the acceleration due to gravity on Earth at sea level?
I'm assuming that the devs used an earth-like parameter for Kerbin, and obviously this math is working for you; but do you use a different acceleration parameter when calculating the delta-V of your Munar return stage? --Hovissimo (talk) 19:45, 25 December 2012 (UTC)<P> No, the 'g' is a standard unit of measurement. Changing it would be like changing the length of a metre because the Mun "has less of them". Kahlzun (talk) 07:37, 2 January 2013 (UTC)
- Isn't that kind of arbitrary, though? Wouldn't make more sense?
