y = x 3 + 823 r 134 f arcsin 2 arcsin 2 ∈ ∫ 1 3 x ∀ x a b S 0 0 1 0 1 1 1 0 1 1 1 0 {\displaystyle y=x^{3}+823r134f\arcsin {\sqrt {2}}\arcsin {\sqrt {2}}\in \int _{1}^{3}x\forall x{\begin{array}{|c|c|c|}a&b&S\\\hline 0&0&1\\0&1&1\\1&0&1\\1&1&0\\\end{array}}}
