Talk:IX-6315 "Dawn" Electric Propulsion System

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Revision as of 18:55, 29 July 2017 by DanielLC (talk | contribs) (Power consumption)
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Power consumption

I was bored and did the math on how much power this thing should take.

Force = 2 kN

Flow rate = 48.5 g/s

Effective exhaust velocity = force / flow rate = 41237.1134 m/s

Specific kinetic energy = 1/2 effective exhaust velocity^2 = 850249761 m^2/s^2

Power consumption = 3.666⚡/s >= specific kinetic energy * flow rate = 41.2371134 MW

1⚡ >= 11.2485306601 MJ

So apparently a ⚡ is a lot of electricity. Now I wonder how horribly inefficient all the other engines are. And how bright Kerbol is.