Difference between revisions of "Talk:Parachute"

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(Full-deployment altitudes depending on pressure?)
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:::Here it is: [http://www.youtube.com/watch?v=yj0T-ylVbjU&t=45m40s http://www.youtube.com/watch?v=yj0T-ylVbjU]. The landing is in the last few minutes. --[[User:Dgelessus|Dgelessus]] ([[User talk:Dgelessus|talk]]) 15:37, 9 May 2013 (CDT)
 
:::Here it is: [http://www.youtube.com/watch?v=yj0T-ylVbjU&t=45m40s http://www.youtube.com/watch?v=yj0T-ylVbjU]. The landing is in the last few minutes. --[[User:Dgelessus|Dgelessus]] ([[User talk:Dgelessus|talk]]) 15:37, 9 May 2013 (CDT)
 
:::: Here is the same video link with time code http://www.youtube.com/watch?v=yj0T-ylVbjU&t=45m40s. --[[User:Omega|Omega]] ([[User talk:Omega|talk]]) 11:19, 10 May 2013 (CDT)
 
:::: Here is the same video link with time code http://www.youtube.com/watch?v=yj0T-ylVbjU&t=45m40s. --[[User:Omega|Omega]] ([[User talk:Omega|talk]]) 11:19, 10 May 2013 (CDT)
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== Semi-deployment altitudes ==
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 +
The semi-deployment altitudes listed in the table are not correct for version 1.0.x.  It appears the altitudes are computed using an outdated formula that is not compatible with the new atmosphere models.  I've computed what the altitudes should be (see table below) but I don't how to edit the table imbedded in the article.  If there is somebody else who knows how to do this, I request that you make the appropriate changes.  Thanks. — [[User:OhioBob|OhioBob]] ([[User talk:OhioBob|talk]]) 05:51, 30 May 2015 (UTC)
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{| class="wikitable"
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|-
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!  !! Eve !! Kerbin !! Duna !! Jool !! Laythe
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|-
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| '''0.04 atm''' || 71 103 m || 44 367 m || 37 739 m || 197 508 m || 46 815 m
 +
|-
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| '''0.02 atm''' || 74 179 m || 48 544 m || 41 381 m || 198 243 m || 47 760 m
 +
|}

Revision as of 05:51, 30 May 2015

Full-deployment altitudes depending on pressure?

Hey, there were some edits, that the full deployment altitudes are depending on the pressure like the semi deployment. Now I haven't visited another planet, but according to the part.cfg (e.g. Mk16) the full deployment altitude is defined by the altitude itself and not the surrounding pressure. Can somebody test this and may back this up? — xZise [talk] 14:39, 8 May 2013 (CDT)

The full deployment altitude is always 500 m above ground. That makes a pressure-based trigger impossible, because the air pressure does not "follow" the terrain. (e. g. on a 10km high mountain the air is thinner than at sea level, but the parachutes will fully deploy at 10500m anyway.) It might be possible that the full-deploy height is different for each planet, but there is no config file for such values. Also it would cause the parachutes to deploy much sooner on Eve than they would on Kerbin, because of its high atmospheric pressure. I haven't been there myself, but I checked a video, the parachutes deployed at 1700m, the landing was at 1200m, so 500m above ground. There is no way that this is pressure-controlled. --Dgelessus (talk) 15:34, 8 May 2013 (CDT)
Ah nice ;) Maybe link the video. I'm now changing this article back. — xZise [talk] 16:32, 8 May 2013 (CDT)
Here it is: http://www.youtube.com/watch?v=yj0T-ylVbjU. The landing is in the last few minutes. --Dgelessus (talk) 15:37, 9 May 2013 (CDT)
Here is the same video link with time code http://www.youtube.com/watch?v=yj0T-ylVbjU&t=45m40s. --Omega (talk) 11:19, 10 May 2013 (CDT)

Semi-deployment altitudes

The semi-deployment altitudes listed in the table are not correct for version 1.0.x. It appears the altitudes are computed using an outdated formula that is not compatible with the new atmosphere models. I've computed what the altitudes should be (see table below) but I don't how to edit the table imbedded in the article. If there is somebody else who knows how to do this, I request that you make the appropriate changes. Thanks. — OhioBob (talk) 05:51, 30 May 2015 (UTC)

Eve Kerbin Duna Jool Laythe
0.04 atm 71 103 m 44 367 m 37 739 m 197 508 m 46 815 m
0.02 atm 74 179 m 48 544 m 41 381 m 198 243 m 47 760 m