Difference between revisions of "Cheat sheet"
From Kerbal Space Program Wiki
(* use <math> tags for some formulas. ! other stuff.) |
(* formulas to <math>. ! other stuff.) |
||
Line 1: | Line 1: | ||
Kerbal Space Program rocket scientist's '''cheat sheet''': Delta-v maps, equations and more for your reference so you can get from here to there and back again. | Kerbal Space Program rocket scientist's '''cheat sheet''': Delta-v maps, equations and more for your reference so you can get from here to there and back again. | ||
− | == Delta-v (Δv) == | + | == Mathematics == |
− | === Basic calculation === | + | === Delta-v (Δv) === |
+ | ==== Basic calculation ==== | ||
#For atmospheric ΔV value, use atmospheric thrust values. | #For atmospheric ΔV value, use atmospheric thrust values. | ||
− | #For vacuum | + | #For vacuum Δv value, use vacuum thrust values. |
#Use this equation to figure out the Δv per stage: | #Use this equation to figure out the Δv per stage: | ||
Line 17: | Line 18: | ||
:<math>\Delta{v} = ln(\frac{23t}{15t}) \cdot 120 s \cdot 9.81 \frac{m}{s^2} = 1803.2 \frac{m}{s^2}</math> | :<math>\Delta{v} = ln(\frac{23t}{15t}) \cdot 120 s \cdot 9.81 \frac{m}{s^2} = 1803.2 \frac{m}{s^2}</math> | ||
− | === Transitional Δv (true Δv when launching from Kerbin) === | + | ==== Transitional Δv (true Δv when launching from Kerbin) ==== |
#How to calculate the Δv of a rocket stage that transitions from Kerbin atmosphere to vacuum. | #How to calculate the Δv of a rocket stage that transitions from Kerbin atmosphere to vacuum. | ||
#Assumption: It takes approximately 1000 m/s<sup>2</sup> of Δv to escape Kerbin's atmosphere before vacuum Δv values take over for the stage powering the transition. | #Assumption: It takes approximately 1000 m/s<sup>2</sup> of Δv to escape Kerbin's atmosphere before vacuum Δv values take over for the stage powering the transition. | ||
Line 29: | Line 30: | ||
*Example: | *Example: | ||
− | :Single stage with total atmospheric Δv of 5000 m/s<sup>2</sup> and with a Δv of 6000 m/s<sup>2</sup> in vacuum. | + | :Single stage with total atmospheric Δv of 5000 m/s<sup>2</sup> and with a Δv of 6000 m/s<sup>2</sup> in vacuum. |
:<math>\Delta{v}_T = \frac{5000 \frac{m}{s^2} - 1000 \frac{m}{s^2}}{5000 \frac{m}{s^2}} \cdot 6000 \frac{m}{s^2} + 1000 \frac{m}{s^2} = 5800 \frac{m}{s^2}</math> | :<math>\Delta{v}_T = \frac{5000 \frac{m}{s^2} - 1000 \frac{m}{s^2}}{5000 \frac{m}{s^2}} \cdot 6000 \frac{m}{s^2} + 1000 \frac{m}{s^2} = 5800 \frac{m}{s^2}</math> | ||
− | === Δv maps === | + | ==== Δv maps ==== |
Various maps developed by KSP fans. | Various maps developed by KSP fans. | ||
Line 43: | Line 44: | ||
#http://ubuntuone.com/1kD39BCoV38WP1QeG6MtO6 | #http://ubuntuone.com/1kD39BCoV38WP1QeG6MtO6 | ||
− | == Thrust to weight ratio (TWR) == | + | === Thrust to weight ratio (TWR) === |
#This is Newton's Second Law. | #This is Newton's Second Law. | ||
− | #If ratio is less than 1, | + | #If ratio is less than 1, the craft will not lift off the ground. |
− | |||
*Equation: | *Equation: | ||
− | : | + | :<math>TWR = \frac{F}{m \cdot g}</math> |
*Explained: | *Explained: | ||
− | : | + | :<math>TWR = \frac{Thrust Force}{Total Mass \cdot 9.81}</math> |
*Example: | *Example: | ||
− | :200 | + | :200 kN rocket engine under a 15 t rocket launching from Kerbin. |
− | :TWR = 200 kN | + | :<math>TWR = \frac{200 kN}{15 t \cdot 9.81 \frac{m}{s^2}} = 1.36</math> |
− | + | :The TWR is higher than 1, so the craft will lift off! | |
− | == Combined specific impulse ( | + | === Combined specific impulse (I<sub>sp</sub>) === |
− | # | + | #If the I<sub>sp</sub> is the same for all engines in a stage, then the I<sub>sp</sub> is equal to a single engine. So six engines with 200 s of I<sub>sp</sub> still yield only an I<sub>sp</sub> of 200 s. |
− | # | + | #If the I<sub>sp</sub> is different for engines in a single stage, then use the following equation: |
*Equation: | *Equation: | ||
− | : | + | :<math>I_{sp} = \frac{(F_1 + F_2 + ...)}{\frac{F_1}{I_{sp1}} + \frac{F_2}{I_{sp2}} + ...}</math> |
*Explained: | *Explained: | ||
− | : | + | :<math>I_{sp} = \frac{Thrust Of Engine 1 + Thrust of Engine 2 + ...}{\frac{Thrust Of Engine 1}{I_{sp} Of Engine 1} + \frac{Thrust Of Engine 2}{I_{sp} Of Engine 2} + ...}</math> |
*Example: | *Example: | ||
− | :Two engines, one | + | :Two engines, the first one with 200 N of thrust and 120 s of I<sub>sp</sub>; the second one with 50 N of thrust and 200 s of I<sub>sp</sub>. |
− | : | + | :<math>I_{sp} = \frac{200 N + 50 N}{\frac{200 N}{120 s} + \frac{50 N}{200 s}} = 130.89 s</math> |
== See also == | == See also == |
Revision as of 18:23, 25 June 2013
Kerbal Space Program rocket scientist's cheat sheet: Delta-v maps, equations and more for your reference so you can get from here to there and back again.
Contents
Mathematics
Delta-v (Δv)
Basic calculation
- For atmospheric ΔV value, use atmospheric thrust values.
- For vacuum Δv value, use vacuum thrust values.
- Use this equation to figure out the Δv per stage:
- Equation:
- Explained:
- Example:
- Single stage rocket that weighs 23 t when full, 15 t when fuel is emptied, and has an engine with a specific impulse of 120 s.
Transitional Δv (true Δv when launching from Kerbin)
- How to calculate the Δv of a rocket stage that transitions from Kerbin atmosphere to vacuum.
- Assumption: It takes approximately 1000 m/s2 of Δv to escape Kerbin's atmosphere before vacuum Δv values take over for the stage powering the transition.
- Note: This equation is an approximation and not completely accurate, so the results will vary a bit depending on the TWR and such. The result is accurate enough for normal purposes though.
- Equation:
- Explained:
- Example:
- Single stage with total atmospheric Δv of 5000 m/s2 and with a Δv of 6000 m/s2 in vacuum.
Δv maps
Various maps developed by KSP fans.
- Δv Total Values
- http://wiki.kerbalspaceprogram.com/w/images/7/73/KerbinDeltaVMap.png
- http://www.skyrender.net/lp/ksp/system_map.png
- Δv Change Values
- Δv KSP Nomogram
Thrust to weight ratio (TWR)
- This is Newton's Second Law.
- If ratio is less than 1, the craft will not lift off the ground.
- Equation:
- Explained:
- Example:
- 200 kN rocket engine under a 15 t rocket launching from Kerbin.
- The TWR is higher than 1, so the craft will lift off!
Combined specific impulse (Isp)
- If the Isp is the same for all engines in a stage, then the Isp is equal to a single engine. So six engines with 200 s of Isp still yield only an Isp of 200 s.
- If the Isp is different for engines in a single stage, then use the following equation:
- Equation:
- Explained:
- Example:
- Two engines, the first one with 200 N of thrust and 120 s of Isp; the second one with 50 N of thrust and 200 s of Isp.
See also
Links to collections of reference materials.