Difference between revisions of "Talk:Kerbol"
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:::::Yeah the thermometer isn't really useful to get accurate temperature readings, but there is liquid water at Kerbin's surface (at normal pressure) which limits the output range of the Sun. But then there is obviously the problem on how to explain the liquid water at Laythe's surface. — [[User:XZise|xZise]] <small>[[[User talk:XZise|talk]]]</small> 05:41, 20 January 2015 (CST) | :::::Yeah the thermometer isn't really useful to get accurate temperature readings, but there is liquid water at Kerbin's surface (at normal pressure) which limits the output range of the Sun. But then there is obviously the problem on how to explain the liquid water at Laythe's surface. — [[User:XZise|xZise]] <small>[[[User talk:XZise|talk]]]</small> 05:41, 20 January 2015 (CST) | ||
::::::You're definitely right about the physical inconsistency of the solar system. However, since the article gave Kerbol's luminosity, and I didn't see anybody questioning that, I thought we should make the star's temperature (and spectral class) consistent with the luminosity. Even though the system is inconsistent, we should at least strive for some internal consistency in the reported characteristics of Kerbol. —[[User:OhioBob|OhioBob]] ([[User talk:OhioBob|talk]]) 22:00, 20 January 2015 (CST) | ::::::You're definitely right about the physical inconsistency of the solar system. However, since the article gave Kerbol's luminosity, and I didn't see anybody questioning that, I thought we should make the star's temperature (and spectral class) consistent with the luminosity. Even though the system is inconsistent, we should at least strive for some internal consistency in the reported characteristics of Kerbol. —[[User:OhioBob|OhioBob]] ([[User talk:OhioBob|talk]]) 22:00, 20 January 2015 (CST) | ||
+ | :::::::Hay! I'm here and I am questioning your luminosity results, because there is no valid and consequent thermal laws in the Kerbal world what you have used. There ara only definite the color (T) and the size (A) can be used for. [[User:NWM|NWM]] ([[User talk:NWM|talk]]) 01:45, 21 January 2015 (CST) |
Revision as of 07:45, 21 January 2015
I know the sun has been called kerbol for a long time, but ingame, it is simply 'the sun'. Kerbol only exists in the memories of old timers. This should be mentioned here.
Contents
M class? More like K...
Based upon the distance to Kerbin, to have earth-like temperatures the star would need to be a low K class minimum. K class stars are still red, so just because 'Red Dwarf' is commonly associated with M class doesn't mean that all red dwarfs are M class.
Just saying, I think it's more likely that kerbol is a K class Main sequence star (KnV, where n is either 6,7, or 8.) --Mocha2007 (talk) 16:05, 18 September 2012 (UTC)
- I have been doing some crude maths of my own on this, and based on the Mass of Kerbol and thus the Luminosity, I see this as being something more like high G, around 8 or 9. Though it does look like it is a very small star for such mass and luminosity. Though This is based of of the mass and radius given from this wiki, which I do not know how accurate they are. Thecoshman (talk) 12:22, 9 October 2012 (UTC)
Use of Planet Box
As the very name suggest, the planet box is for planets, much of the information it would contain is 'N/A' when dealing with stars. Could someone with a better mastery of templates make a more applicable 'star box'. It may seem a bit redundant for the now, but I dare say eventually inter-stellar travel will be possible. Thecoshman (talk) 08:21, 9 October 2012 (UTC)
Expression Error: Unexpected < Operator
Ok... I wanted to change the class of Kerbol form star to K-Class Star. It worked, but in bright red letters popped the message: "Expression Error: Unexpected < Operator". So like the good person i am, i reverted my changes, but it stayed. I think it has something to do with the Orbital Period Hours. Anybody know what the heck is going on???--Azivegu (talk) 19:24, 22 October 2012 (UTC)
Dutch link
Could somebody link up the Dutch language Kerbol Page to this one like the Russian one is done???--Azivegu (talk) 19:25, 22 October 2012 (UTC) http://wiki.kerbalspaceprogram.com/wiki/Kerbol/nl - but im translating it: WIP --ExtremeTrader (talk) 5:54, 19-12-2013 (BST)
Kerbol
Though it probably is indeed a K-class, it may also be a white dwarf. If Kerbol actually existed, it would be a T or Y class brown dwarf, because no star that small can undergo nuclear fusion.--Mocha2007 (talk) 22:25, 28 October 2012 (UTC)
Trivia Terminology
most of the terms used in the trivia and the best ways of getting to Kerbol are terms that I myself don't understand. I'm going to look them up, but as a suggestion, I'd reccomend a link to a wikipedia article for what they mean
Answer: http://wiki.kerbalspaceprogram.com/wiki/Terminology --ExtremeTrader (talk) 00:02, 19 December 2013 (CST)
Name
The name of the Star in-game is "Sun", so I'm unsure as to why the name of this page is "Kerbol", surely it should be the same as in-game? — Preceding unsigned comment added by Ted (talk • contribs)
- It's partly historical reasons (the name "Kerbol" predates the star being an object by some time), and as a way to distinguish the star from our Sun (It's frustrating getting newbies to realize that Kerbin != Earth, Mün != Luna, etc). The name is fairly entrenched in the game population at this point, though I wouldn't mind if Squad picked a wholly new one... UmbralRaptor (talk) 22:25, 12 February 2013 (CST)
- I support this. Calling the page "Kerbol" does nothing except help spread misinformation Holomanga (talk) 09:38, 27 May 2013 (CDT)
- Now but this isn't the real Sun. Luckily you can differ between Kerbal celestial bodies and real ones by the name, except for the Sun. As there is a redirect from Sun although those who searching for it get redirected here. And it is stated that it is also called the Sun in the first sentence. But I made it clearer that “the Sun” is the official name. — xZise [talk] 11:38, 27 May 2013 (CDT)
Rotation speed
If you go into interplanetary space, and check the 'surface' speed indicator, you will see the surface is spinning at well over 700 km/s.. should this be updated? — Preceding unsigned comment added by Kahlzun (talk • contribs)
- The orbital velocity at the surface is okay 67 km/s which would result in the sun ripping apart. — xZise [talk]
- The "surface" indicator on the navball actually indicates how fast you move in relation to the surface. --dgelessus (talk, contribs) 11:35, 27 May 2013 (CDT)
Outdated Surface height
Unless I somehow read the page wrong, the invisible surface height of ~4500 km is outdated as of 0.21.1, proved by my small sundiving probe currently at ~4000 km. - JonSpace_CEO (i'm also unsure of how to timestamp as i'm new to the wiki)
Just went back and checked, the new lowest altitude is ~1300 meters , not ~4500 km (with screenshots to prove it)
- Note: You can sign your posts with --~~~~.
- What does the altimeter read, when you crash somewhere else into Kerbol? If it is almost always about 1.3 km this should be fixed. — xZise [talk] 03:51, 8 September 2013 (CDT)
Can we possibly get someone else to do it as i don't really feel like repeatedly crashing probes into the sun (it gets kinda monotonous) also, i'm fairly busy with some stuff right now so i can't do it anytime soon. --JonSpace CEO (talk) 04:59, 12 September 2013 (CDT) (thanks for the tip on signing btw)
Confirmed, I blew up around 1300m as well. --Dentarthurdent (talk) 18:05, 23 October 2013 (CDT)
All engines have a TWR below 1 at the surface?
I haven't tested it yet, but why is the TWR of all engines below 1? In the parts article are all engines listed with their TWR on Kerbin's surface. But the surface gravity is only listed as 17.1 m·s⁻² or ≃ 1.76 g. So the TWR on Kerbol is the TWR of Kerbin divided by 1.76, which means that each engine with a TWR at Kerbin greater than 1.76 will have a TWR at Kerbol's surface greater than 1. And most engines have a listed TWR of 1.76. So is there another “force“ at work, or is this simply outdated? It appears that prior to 0.14 you could drop below the surface and thus increasing the TWR drastically, although I'm not sure what the gravitational acceleration is at the center. — xZise [talk] 18:33, 6 October 2013 (CDT)
- Yes, this seems incorrect. Assuming a spacecraft consisting of just the engine with a massless fuel source, the Mainsail should have a TWR of 14.1 at the surface. Skipper would have a TWR of 9.2, and even the nuclear engine would have a TWR of 1.6. I haven't checked all of the engines but it looks like most would easily work for a lander. Mocha2007 (talk) 11:06, 14 October 2013 (CDT)
spectral classes
“ | It has the temperature of a K Class main sequence star, the radius of a M class star, the luminosity of a G class star, and the mass of a sub-brown dwarf. In reality, such a star cannot exist as the minimum mass of a star is approximately 75 times the mass of Jupiter, a full power of ten higher than that of Kerbol. | ” |
No offense, but I don't think the writer of this sentence really knows how to read an HR diagram. the type or class of a star denotes the temperature and color of a star, not the luminosity or the size. For example, the "radius of an M-class star" as mentioned above, can vary anywhere from the size of a red dwarf like Barnard's Star, to a red supergiant like Betelgeuse. Similarly, as the type denotes temperature and not luminosity, G type stars can be nearly anywhere on the luminosity range, from dim yellow dwarfs to bright yellow supergiants. I'm not sure about exactly what type of star Kerbol is, but this sentence needs to be changed.-Cpthunt (talk) 19:56, 4 November 2013 (CST)
- As you already created an account you are able to fix it yourself. Of course you can still add a note in the discussion to explain it more detailed. I've edited your original comment to avoid that the MediaWiki treats your quote as code (leading whitespaces). — xZise [talk] 10:59, 5 November 2013 (CST)
I really have to disagree with everyone calling Kerbol a K-class star. I agree that, based on Kerbin's temperature, Kerbol's luminosity must be about 3E+24 watts. However, given its surface area, that works out to a luminosity of 3.5E+6 watts/m^2. Using Stefan-Boltzmann law, this computes to a surface temperature of 2800 K, which clearly makes it an M-class star. Can someone show me how you're coming up with K-class?--OhioBob (talk) 1:20, 17 January 2015 (UTC)
- And I really disagree with you. The sentence was correct, the temperature always determined by the color see this, and the luminosity determines the emitted power. NWM (talk) 18:33, 17 January 2015 (CST)
- If the 2,8 kK mentioned by OhioBob are the w:effective temperature mentioned in w:Stellar classification#Harvard spectral classification it'd classify as a M class star. As I understand it, the color and temperature are linked (higher temperature means white and then blue) and either the temperature at Kerbin is wrong, Kerbin's distance, Kerbol's size or Kerbol's color ;) I guess Squad just didn't thought that there would be people who would try to determine the star's class. — xZise [talk] 18:51, 17 January 2015 (CST)
- Although it is true there is a temperature-color relationship, spectral class is determined by temperature. Color can be used as an indicator of temperature, but temperature can be determined in other ways. In this case the temperature can be determine mathematically based on other known factors (Kerbin's temperature & distance, and Kerbol's size). This results in a computed surface temperature of 2800 K, making Kerbol a M class star. The math should be the determining factor, not what it looks like. Kerbol's yellow-orange color is simply a mistake given what we can mathematically determine about it. — OhioBob (talk) 9:06, 19 January 2015 (UTC)
- Let me also add that if Kerbol were a K class star, it would have a surface temperature of at least 3700 K. At this temperature its luminosity would be about 9 Yotta-watts. This would place Kerbin well inside of the star's habitable zone. Kerbal life as we know it would not be possible if Kerbol were K class. — OhioBob (talk) 16:58, 19 January 2015 (UTC)
- At first - in the Kerbal World we cannot estimate the power emission of the Kerbol, because this world is not physically consistent - the solar panels power generation doesn't follow the inverse square law, neither the celestials surface temperature. You will get different result by each of the celestials. By the parameters of Laythe it would even more then ~5000K derived from the color!— Preceding unsigned comment added by NWM (talk • contribs) 07:09, 20 January 2015 (UTC)
- Yeah the thermometer isn't really useful to get accurate temperature readings, but there is liquid water at Kerbin's surface (at normal pressure) which limits the output range of the Sun. But then there is obviously the problem on how to explain the liquid water at Laythe's surface. — xZise [talk] 05:41, 20 January 2015 (CST)
- You're definitely right about the physical inconsistency of the solar system. However, since the article gave Kerbol's luminosity, and I didn't see anybody questioning that, I thought we should make the star's temperature (and spectral class) consistent with the luminosity. Even though the system is inconsistent, we should at least strive for some internal consistency in the reported characteristics of Kerbol. —OhioBob (talk) 22:00, 20 January 2015 (CST)
- Yeah the thermometer isn't really useful to get accurate temperature readings, but there is liquid water at Kerbin's surface (at normal pressure) which limits the output range of the Sun. But then there is obviously the problem on how to explain the liquid water at Laythe's surface. — xZise [talk] 05:41, 20 January 2015 (CST)
- At first - in the Kerbal World we cannot estimate the power emission of the Kerbol, because this world is not physically consistent - the solar panels power generation doesn't follow the inverse square law, neither the celestials surface temperature. You will get different result by each of the celestials. By the parameters of Laythe it would even more then ~5000K derived from the color!— Preceding unsigned comment added by NWM (talk • contribs) 07:09, 20 January 2015 (UTC)
- If the 2,8 kK mentioned by OhioBob are the w:effective temperature mentioned in w:Stellar classification#Harvard spectral classification it'd classify as a M class star. As I understand it, the color and temperature are linked (higher temperature means white and then blue) and either the temperature at Kerbin is wrong, Kerbin's distance, Kerbol's size or Kerbol's color ;) I guess Squad just didn't thought that there would be people who would try to determine the star's class. — xZise [talk] 18:51, 17 January 2015 (CST)