Talk:Kerbin
Contents
- 1 Wrong Orbit display
- 2 In-Game Descriptions
- 3 Infobox
- 4 Links
- 5 'Kermunist'
- 6 Atmosphere
- 7 Orbital information
- 8 Sidereal day length changed
- 9 Map
- 10 Orbits
- 11 Map
- 12 Making Geosynchronous Orbit More Exact?
- 13 Elevation update
- 14 Surface gravity
- 15 G factor
- 16 KSC Biomes.
- 17 Atmosphere: altitude vs. pressure
- 18 Atmosphere composition
- 19 Atmosphere — version 1.0 changes
- 20 Terminal Velocity
- 21 Sidereal Rotation Period
- 22 modded picture
- 23 Easter Eggs
- 24 No changes, but presumably incorrect info found.
- 25 It can't be so spherical
- 26 Atmospheric height fix
Wrong Orbit display
I'm a newbie and don't really know how to edit that, but it looks like all the apoapsis/periapsis display are incorrect for a lot of celestial bodies. In the wiki, Kerbin have a 13 599 840 256 m apoapsis/periapsis while in game it's 13 338 240 256 m. Even if you add/substract 600 000 m it's incorrect. - Indeed 14:54, 23 December 2014 UTC
- The value here includes Kerbol's radius (261 600 000 m), while the map view display does not UmbralRaptor (talk) 13:05, 23 December 2014 (CST)
In-Game Descriptions
Should we really be correcting Squad's grammar? If we do then they aren't quotes anymore. None of the descriptions contain apostrophes even on words like "dont" so I don't mind adding them in but otherwise I strongly advocate against correcting grammar. The quotes should be quotes. Now since I only have one computer and the game won't function for me unless it is in full screen, I couldn't view both the in-game description and my transcription of it at the same time so I may have made some copping errors (though I did form a check on each) and these should be corrected. I don't mind going back cheeking and correcting the quotes though I won't be able to until later (probably in a few days) but I thought I would discuss my reasoning here first before I do. I don't want to get into an update war. - benschwab 17:36, 29 March 2014 UTC
Hi Ben! No, I agree with you; literal quotes must be literal. I could have made that clearer in my edit summaries. I meant I was correcting to match Squad's bad grammar. No war. But I have two computers and checked all the descriptions to be exactly as Squad has them in-game – Dres is particularly ungrammatical... --Brendan (talk) 19:50, 29 March 2014 (CDT)
Kay. Thank you. I must of have been auto editing while switching between windows and mis-read what you were doing. I appreciate you correcting my mistakes. - benschwab 5:02, 30 March 2014 UTC
Infobox
I've attempted to make an infobox template for planets, Template:Infobox/Body, to bring it closer in line to the stock parts here and planets on wikipedia. Any advice would be welcome. — Preceding unsigned comment added by Craigmt (talk • contribs)
- So far, so good. I think you have more columns than you originally anticipated, though, so many of the cellss are floating around. -- N3X15 (talk) 19:22, 24 September 2012 (UTC)
- Yeah, the length of the template is breaking some formatting stuff on articles it's transcluded in. It looks good, but I'd personally trim it down to mass/diameter/etc. and leave orbital information in the article proper. -- Trinexx ► 19:34, 24 September 2012 (UTC)
So, leave orbital characteristics in the article itself and keep physical characteristics in the box? — Preceding unsigned comment added by Craigmt (talk • contribs)
- That's my personal recommendation, at least. I imagine other people have their own opinions on the matter. -- Trinexx ► 20:40, 24 September 2012 (UTC)
Links
All the links used in the references are broken. Just an FYI. -- N3X15 (talk) 09:55, 1 October 2012 (UTC)
'Kermunist'
Should this term really be used? Thecoshman (talk) 18:28, 7 October 2012 (UTC)
- There are no factions in the game, so it would be better to not have that in there, as it'd cause confusion. We do need a Manual of Style to cover stuff like this. -- N3X15 (talk) 20:30, 7 October 2012 (UTC)
Atmosphere
I edited the atmosphere section to make clear the units of d_k & p_k after working through gamedata. Still unsure what units p_k are in FlightGlobals.getStaticPressure() values are in atm, with 1 atm = 101325 Pa to get an absolute static pressure value needed for ideal gas law
-Kellven
Should it be mentioned that because Kerbin has plant and animal life, that therefore the atmosphere is similair to our own? That would be a bit quick on the draw given that even our atmosphere is extremly hostile to some earthbound organisms.
--Azivegu (talk) 08:33, 13 December 2012 (UTC)
Orbital information
it mentions in the infobox that Kerbin has a o ecc and 0 inc orbit.. i don't think thats correct, can someone plug the correct figures in?
- Maltesh's rip of the 0.18.2 orbital parameters has those, and a quick check in map view shows Kerbin's altitude and speed not changing anywhere in the orbit, so it should still be correct. UmbralRaptor (talk) 06:48, 1 February 2013 (CST)
- I'm not sure it's the best place for this information, but I linked to the planetary data spreadsheet and text files at Celestials#Notes. — Elembis (talk) 10:54, 1 February 2013 (CST)
Well, that will teach me to open my big mouth before checking my facts. I guess the inclination of the other bodies is measured relative to Kerbin. Oops. Kahlzun (talk) 21:14, 8 February 2013 (CST)
Why is sidereal orbital period showed in Earth days (106 days 12 hours 32 min)? That has no use, it obviously should be in Kerbin days: 426 days 32 min. I have Kerbin calendar and want to know how many days it takes to Kerbin to cover X radians. --Masuk (talk) 09:59, 28 January 2015 (CST)
- It was from before Squad redefined 1 Kerbin day to 6 hours. Before that all calculations used 24 hours. And “obviously” that isn't obviously as it's not visible which day length is chosen (Kerbin's sidereal day, Kerbin's solar day, Earth's sidereal day or Earth's solar day). It seems obvious for Kerbin, but not for the other celestial bodies. — xZise [talk] 10:43, 28 January 2015 (CST)
Sidereal day length changed
With the release of 0.24 the solar day is now exactly 6 hours long. Is my understanding correct? What would make the sidereal day then? Is there an objection to updating the page to reflect this new information? Benschwab (talk) 20:25, 24 July 2014 (UTC)
- I'm not sure if that hadn't already changed before. — xZise [talk] 17:14, 25 July 2014 (CDT)
- Okay thanks to User:UmbralRaptor on the IRC I was able to make calculations. He placed a command pod on top of the launch pad at a altitude of 72 m in 0.19, 0.23.5 and 0.24.2 and always gets a orbital velocity of 174.6 m/s.
- The orbital velocity while standing on the surface is basically the rotational speed at that altitude. Now using we can calculate the time required to do a full circle with a radius of 600 072 m: = = 21594 seconds (or 5h 59m 54s) which is almost 6 hours. When you do the reverse you get 174 554 mm/s which rounded gets you 174.6 m/s. This makes me already pretty confident that the sidereal rotation is 6 hours and not the solar day.
- Now lets give it a chance and use 6 hours as a solar day. But to calculate the rotational velocity the value needs to be converted into the sidereal rotation period, because on the way how the calculation works: When viewed from the north (or south) pole the craft on the launch pad is doing a circle and the circumference depends on the radius. To calculate a constant speed (a little physics: the velocity vector changes because the craft "curves" but the magnitude stays the same which is afaik called speed) the distance has to be divided by the time it took to cover that distance. The distance, is the circumference and the time it took that distance is the sidereal rotation period. If you use the solar day for that time you would need a larger distance (in this case, in theory the solar day can be shorter than the sidereal day) because Kerbin does rotate a bit further.
- To convert that I used the formula from Wikipedia and plugged in the solar day length and sidereal orbit: 21459 seconds (or 5h 59m 9s) (for validity of the formula, c is the orbital period, x is the length of the solar day and y is the length of the sidereal day)
- Using that we get 174 964 mm/s which is rounded 175 m/s. But that speed is considerably larger compared the previous result.
- We also checked if the orbit has changed (which would have changed the length of a sidereal day if the solar day is fixed at 6 hours and got 13338240256m which is 261600000m lower than the value shown here in the infobox (13599840256 m) but is exactly the radius of Kerbol. And the altitude in KSP is given from the body's surface so that checks out. But even though the orbit must have been considerably larger to get solar day and sidereal day close (and I'm currently not in the mood to determine how large the orbit must be that both length of days are close enough that solar day length would make sense).
- So unless we didn't consider a specific factor I gather that the length of the sidereal day hasn't changed contrary to the changelog.
- Also if you think about it, what would be the advantage. Defining times based on their sidereal values makes it easier because you don't have to take the orbit into account. I also revert the change in the infobox to a sidereal day length of exactly 6 hours. — xZise [talk] 22:22, 4 August 2014 (CDT)
Map
Does anyone now what projection the map is in? a link to the relevant page would be nice, i am refering to the one in the Topography section
- What map do you mean? — xZise [talk] 02:37, 22 April 2013 (CDT)
- I would guess Equirectangular projection as the one degree in both axes in File:Kerbin heightmap.jpg have always the same length. — xZise [talk] 08:15, 18 May 2013 (CDT)
Orbits
I crunched the numbers using a few different methods and I keep getting a discrepancy between my numbers and the listed figures (I calculate a GEO orbital velocity of ≈1109 m/s, a difference of exactly 100 m/s). Can someone confirm this? Otherwise, tell me why I'm wrong. ;) -- Eurousalas (talk) 14:51, 22 April 2013 (EST)
- I can confirm both. This confirm your value while this confirm the value of this page. What formula do you use?
- m = orbited body mass, p = orbital period
- — xZise [talk] 14:54, 22 April 2013 (CDT)
- Thanks to a friend, I know what your mistake is: The GSO altitude is given relative to the planet's surface not gravity center. Now {{OrbitVelocity}} and wolfram alpha need this value to be from the gravity center. So you need to add 600 km to your altitude and then you get the correct value. — xZise [talk] 15:03, 22 April 2013 (CDT)
- Ack, I knew it would be an obvious mistake. Thanks for pointing that out, it would have bugged me for a long time. -- Eurousalas (talk) 17:46, 27 April 2013 (EST)
- Thanks to a friend, I know what your mistake is: The GSO altitude is given relative to the planet's surface not gravity center. Now {{OrbitVelocity}} and wolfram alpha need this value to be from the gravity center. So you need to add 600 km to your altitude and then you get the correct value. — xZise [talk] 15:03, 22 April 2013 (CDT)
- I did some calculations for Kerbin synchronous orbit and got 1009.8140782005581 m/s and 21549.258066089664 seconds ( 5:59:09.258066 hh:mm:ss) for period. I used G = 6.67408E-11 and Kerbin mass = 5.2915793E+022 Maybe someone can update the wiki.--Baumfaust (talk) 19:49, 6 May 2016 (UTC)
![{\displaystyle v={\sqrt {\frac {G\cdot m}{\sqrt[{3}]{\frac {p^{2}\cdot G\cdot m}{4\cdot \pi ^{2}}}}}}}](https://en.wikipedia.org/api/rest_v1/media/math/render/svg/c9375c7497e0d18fab6a7919849c480f6ac146fd)
Map
I'd like to note that both true-colour maps are outdated. Saik0 on the KSP forums has made maps which are not outdated and in Full-HD and uploaded them on http://www.kerbalmaps.com/ . The website includes anomaly locations (optional), elevation maps, slope maps and true colour maps for all bodies in the Kerbol system except for Kerbol and Jool. He also put those maps online for download at https://mega.co.nz/#F!8EAnSL5Z!OAyLBQqrQtlmfL0GT8fcQg!EBYyXRxA . I have not uploaded any of these images myself yet, because e.g. the Duna true-colour map is something like 77.5 MB where 2 MB are allowed and I'm unable to compress them. I came here to ask if someone would be interested in compressing these for the community. Oh also, here have his KSP forums thread: http://forum.kerbalspaceprogram.com/showthread.php/25148-Web-maps-of-all-bodies-(0-4-ALL-bodies-mapped!)?p=307335#post307335 MmPMSFmM (talk) 07:42, 2 July 2013 (CDT)
- I'm wondering where the Kerbin map is on your download link? Here are my suggestions to compress them:
- Use a compression format like png/jpg
- Reduce the resolution of the image (may not be needed when compressing with jpg)
- — xZise [talk] 08:36, 2 July 2013 (CDT)
- I just found out why you can't find the Kerbin files on that MEGA site: on the forums the author says that "it is his first map and only has half the resolution of the others" and that he will upload it once he redoes it. Also I'm having problems with that MEGA site and Firefox, can't download the files, because of some message about accepting another message that doesn't appear for me... --dgelessus (talk · contribs) 09:23, 2 July 2013 (CDT)
- I'm able to download the images. I tested Gilly but when I tried to edit gilly_0.19.1_0.02197265625_-180_90_180_-90_16384x8192.elevation.tif (which I guess is the most important type of map?) I can't open or edit it because: convert: Sorry, can not handle images with 32-bit samples.. Maybe I find a way to fix this and I'll upload some files. — xZise [talk] 19:10, 2 July 2013 (CDT)
- I just found out why you can't find the Kerbin files on that MEGA site: on the forums the author says that "it is his first map and only has half the resolution of the others" and that he will upload it once he redoes it. Also I'm having problems with that MEGA site and Firefox, can't download the files, because of some message about accepting another message that doesn't appear for me... --dgelessus (talk · contribs) 09:23, 2 July 2013 (CDT)
Making Geosynchronous Orbit More Exact?
I see the formula for the calculation of geosynchronous orbit, but that only gives the orbit within the tens of metres. Through some calculations I've found that the closest I can get is 2868750.72505 metres. Would we be willing to change it?
- Considering that it is practically impossible to get the orbit that exact, I don't think it's necessary. 2868.75km is more than close enough.--Ruedii (talk) 19:13, 23 July 2013 (CDT)
As of 1.2, experimental evidence shows KSO to be approximately 2862.9407km. https://www.reddit.com/r/KerbalSpaceProgram/comments/5a3w6s/a_question_about_keostationary_altitude/--Yehoodig (talk) 03:33, 30 October 2016 (UTC)
- This will get fixed in 1.2.1 as they mentioned in KSP Weekly. --Olympic1 (talk) 15:00, 30 October 2016 (UTC)
Elevation update
With topology changes in 0.21, the highest known elevation will have likely changed. My current efforts with a 52 million sample file from ISA Mapsat show a new highest elevation of 6765.1 at location +61.6,+46.34, but I want to confirm that with a landing before updating the page and also wasn't sure if I had missed any higher points.--Khyron (talk) 02:12, 28 July 2013 (EDT)
Surface gravity
I suggest adding a percentage value to the surface gravity inside the info boxes of the planets. This percentage value, denotes a comparison to Kerbin. So the 9,81m/s² acceleration of is 100%, and the value of other planet is an according value. Another way of denoting this value, would be to set Kerbin's s as 1 and then use that to compare the gravitational acceleration of other planet. Polemon (talk) 14:39, 11 September 2013 (CDT)
- You are talking about using “g-force”: 1 g = 9.81 m/s². This is in theory possible, but I'm not quite sure if this is really helpful. The template is already enormous and Kerbol System/Table for example show them for you. — xZise [talk] 15:06, 11 September 2013 (CDT)
G factor
Does g = 9.82 m/s² ? Specific_impulse#Conversion_factor discusses back-calculating g, and arrives at a value closer to 9.82. Any thoughts on breaking this out in to its own page, or at least "correcting" it here?--BlobKerman (talk) 07:50, 26 May 2014 (CDT)
- The gravitational acceleration at the surface shown in the infobox is calculated, based on the mass and radius of Kerbin and using {{Body data/Gravity}}. So I wouldn't redefine g to 9.82 m/s². The conversion factor is arbitrarily chosen and "coincidentally" the same as the average surface gravity for real-world rockets. You could use 1 m/s² and in the US they would then choose something like 3.3 ft/s² and would get the same results. — xZise [talk] 13:08, 26 May 2014 (CDT)
- At least when I last checked, g for Isp and g for Kerbin's surface did not match up. Hence 9.82 for engine efficiency, but 9.81 for weight. UmbralRaptor (talk) 14:31, 26 May 2014 (CDT)
KSC Biomes.
I've updated the KSC Biome section, I believed there were 11, but reports on the forums are showing that there could be as many as 30? Can anyone verify this? I'll try and take another look later and do a bit more exploration, but I only found 11 on the ground with EVA - Science Alert going off every time I stepped into a new biome. — Preceding unsigned comment added by Severedsolo (talk • contribs) 10:30, 18 October 2014 (UTC)
With 0.25 all the buildings at KSP are distinct biomes. HenrikOOlsen (talk) 02:52, 2 December 2014 (CST)
Atmosphere: altitude vs. pressure
So yesterday I dropped a rescue pod into kerbin and while I waited it to land I kept the barometer display visible and took some readings. I post it here for use of the community.
| Altitude (km) | Pressure (Atm) | Observations |
|---|---|---|
| 46.0 | 0.0001 | |
| 44.0 | 0.0002 | |
| 41.5 | 0.0003 | |
| 39.8 | 0.0004 | |
| 38.5 | 0.0005 | |
| 37.6 | 0.0006 | LV-909 Isp=389.9 |
| 36.8 | 0.0007 | |
| 35.9 | 0.0008 | |
| 35.4 | 0.0009 | |
| 34.8 | 0.0010 | |
| 32.7 | 0.0015 | |
| 31.8 | 0.0018 | LV-909 Isp=389.8 |
| 31.2 | 0.0020 | |
| 29.2 | 0.0030 | |
| 27.7 | 0.0040 | |
| 26.6 | 0.0050 | |
| 25.6 | 0.0060 | |
| 24.8 | 0.0070 | |
| 23.6 | 0.0090 | |
| 23.1 | 0.0100 | |
| 22.5 | 0.0120 | LV-909 Isp=389.0 |
| 20.3 | -- | LV-N Isp=790.0 |
| 19.5 | 0.0200 | |
| 17.6 | 0.0300 | |
| 16.0 | 0.0400 | |
| 15.0 | 0.0500 | LV-909 Isp=385.0 |
| 11.5 | 0.1000 | |
| 11.0 | 0.1200 | LV-909 Isp=380.0 |
| 8.0 | 0.2000 | |
| 7.5 | 0.2500 | LV-909 Isp=370.0 |
| 5.4 | 0.3300 | LV-909 Isp=360.0 |
| 5.3 | -- | LV-N Isp=600.0 |
| 3.5 | 0.5000 | |
| 2.0 | 0.6500 | LV-909 Isp=330.0 |
| 1.3 | 0.7500 | LV-909 Isp=320.0 |
| 0.285 | 0.9400 | LV-909 Isp=305.0 |
Nando.sm (talk) 01:02, 27 October 2014 (CDT)
- It would be interesting to have the corresponding calculated pressure/specific impulse in each row. (although I'm pretty certain those numbers are matching closely) — xZise [talk] 05:37, 27 October 2014 (CDT)
Altitude (km) Pressure (kPa) 0 101.325 72 100.2493 100 99.8063 200 98.3117 300 96.9352 400 95.4177 500 93.9247 600 92.6178 700 91.2165 800 89.8453 900 88.0944 1000 87.2132 1100 85.8961 1200 84.5334 1400 81.9849 1600 79.4859 1800 77.0767 2000 74.6436 2500 68.9846 3000 63.6503 3500 58.7274 4000 54.0454 4500 49.6644 5000 45.6081 5500 41.8373 6000 38.3011 7000 31.9308 7500 29.1033 8000 26.4661 9000 21.8144 10000 17.8642 11000 14.7102 12000 12.1174 13000 9.958 14000 8.17 15000 6.7063 17500 4.1221 20000 2.5405 22500 1.5822 25000 0.9854 27500 0.6326 30000 0.4046 32500 0.2643 35000 0.1742 40000 0.0782 45000 0.036 50000 0.0155 55000 0.0063 60000 0.0024 65000 0.0007
Atmosphere composition
In the atmospheric composition was added. How could that be determined? — xZise [talk] 18:52, 17 January 2015 (CST)
- The gas molecular weight is calculated from the ideal gas law. The known sea level conditions are pressure (101325 Pa), temperature (293.15 K), and density (1.2230948554874 kg/m^3). From this it is a straightforward computation to derive the average gas molecular weight of 29.42 kg/kmol. We know oxygen (M = 32) is present, so for the molecular weight to be 29.42, the balance of the atmosphere must be a gas lighter than M = 29.42. The only candidate gas that can reasonably exist in large abundance is nitrogen (M = 28). Hydrogen, helium and neon are too light and would escape, methane and ammonia are either broken down or removed through natural processes, and carbon monoxide would oxidize to CO2 and be dissolved into the oceans. That leaves just nitrogen, though other gases are likely to exist in small quantity as in Earth's atmosphere (all gases other than nitrogen and oxygen make up just 1% of Earth's atmosphere). Assuming a nitrogen-oxygen atmosphere, the two gases must exist in the proportion needed to yield an average molecular weight of 29.42 kg/mol. This occurs when the percentages are 65% nitrogen and 35% oxygen by volume. — OhioBob (talk) 17:53, 19 January 2015 (UTC)
- Okay that makes mostly sense except that we don't know much about Kerbin's flora and fauna and if it works like on Earth. But using that assumption anything could be possible. — xZise [talk] 05:29, 20 January 2015 (CST)
- I've edited the article to make it more clear what the assumptions are. You are right that there are things about Kerbin that we don't know, but it seems to be the game's intent to make Kerbin Earth-like. If we to go completely sci-fi we can make the atmosphere anything we want; however, if stay with what is scientifically plausible, then the best explanation is a nitrogen-oxygen atmosphere. I've also done some calculations and found that a real-life planet of Kerbin's size wouldn't be able to retain an atmosphere. — OhioBob (talk) 22:48, 20 January 2015 (CST)
- Have you ever heard of reaction kinetics? Have you ever warned not to deal the oxygen containers with oiled hands? Do you know what would happen at 35% concentration of oxygen? Almost everything would catch fire immediately (even the nitrogen when a rocket engines starts)! Why not mix Argon (M=40) in your equation? It is dense, inert and even earth atmosphere contains copious amount of it! NWM (talk) 01:35, 21 January 2015 (CST)
- With three gases it's impossible to calculate the proportions unless one is known; however, adding a heavy gas like argon could certainly bring the oxygen percentage down to something more Earthlike (O2 decreases by about 3% for every 1% of Ar added). I'd certainly be willing to remove the sentence from the article that talks about 65/35 N2/O2 since that might be too big of an assumption to make. However, the part about the molecular weight being 29.42 is entirely valid, as that is computed directly from given data. I also think the part about nitrogen being the other major constituent is a reasonable conclusion. What do you guys think? — OhioBob (talk) 02:14, 21 January 2015 (CST)
- I've removed the part about 65% N2 and 35% O2. Instead I simply said that nitrogen is the "majority constituent", which is almost assuredly true given the molecular weight. — OhioBob (talk) 11:25, 21 January 2015 (CST)
- Also note that the peak oxygen level on Earth was about 35% in the Carboniferous period, so that level is not unprecedented or impossible. — OhioBob (talk) 13:45, 21 January 2015 (CST)
- Have you ever heard of reaction kinetics? Have you ever warned not to deal the oxygen containers with oiled hands? Do you know what would happen at 35% concentration of oxygen? Almost everything would catch fire immediately (even the nitrogen when a rocket engines starts)! Why not mix Argon (M=40) in your equation? It is dense, inert and even earth atmosphere contains copious amount of it! NWM (talk) 01:35, 21 January 2015 (CST)
- I've edited the article to make it more clear what the assumptions are. You are right that there are things about Kerbin that we don't know, but it seems to be the game's intent to make Kerbin Earth-like. If we to go completely sci-fi we can make the atmosphere anything we want; however, if stay with what is scientifically plausible, then the best explanation is a nitrogen-oxygen atmosphere. I've also done some calculations and found that a real-life planet of Kerbin's size wouldn't be able to retain an atmosphere. — OhioBob (talk) 22:48, 20 January 2015 (CST)
- Okay that makes mostly sense except that we don't know much about Kerbin's flora and fauna and if it works like on Earth. But using that assumption anything could be possible. — xZise [talk] 05:29, 20 January 2015 (CST)
Atmosphere — version 1.0 changes
I've updated the atmosphere section to include changes made with the release of v1.0. Much of what was previously written in no longer applicable. For instance, pressure is now evaluated using a floatCurve, thus the old isothermal/constant scale height method no longer works. Atmospheric properties are contained within a configuration file named CelestialBodies.cfg, to which I have access. That facts and figures I've provided are those used within the game. I've also have a couple of images that I want to include that show a graph of temperature and pressure vs. altitude, though I keep getting an error when trying to upload. This may be related to the migration problems that the forum is having. I also couldn't get the formula text to work, which may be related to the same problem. After the migration issue is resolved I hope to add the images and correct the math text. — OhioBob (talk) 17:20, 20 May 2015 (UTC)
Terminal Velocity
I removed the section about terminal velocity because little of what was written is applicable to the new aero model. A table of terminal velocity is meaningless because there are now variable factors that go into it. If anybody wants to rewrite that section, the old text is still there; it has just been bracketed with comment tags so that it doesn't appear in the article. — OhioBob (talk) 17:20, 20 May 2015 (UTC)
- Well there is a version history so they could just use the text from there. — xZise [talk] 16:45, 21 May 2015 (UTC)
Sidereal Rotation Period
Although the Kerbin calendar day is 21600 seconds (6 hours), I just discovered that the actual sidereal period is slightly less. I observed the same star on the eastern horizon on the first day of each year and found that it was rising about 37 seconds sooner each successive year. I warped ahead 20 years and found that it rose a total of 748 seconds earlier, or 37.4 seconds each year. This means that the time it takes the planet to rotate 426 times is 37.4 seconds less than a full year. Therefore, the actual sidereal period is (426*21600-37.4)/426 = 21599.9122 seconds. This makes the solar day 21650.7246 seconds. From this we should find that the Sun rises sooner each successive year by the amount, 426*21600-425*21650.7246 = 42 seconds. Observations have shown that the Sun does indeed rise 42 seconds earlier on the first day of each new year, proving the numbers. OhioBob (talk) 03:26, 28 July 2015 (UTC)
modded picture
the picture for the data table shows Kerbin with several visual enhancement mods, shouldn't we show Kerbin using the stock visuals? I may change this if no one objects
Easter Eggs
The other day my probe hit Kerbin, and I spotted some white pixels on the surface just before the crash landing. I zoomed in on these and they were infact rocks which create definite reliefs in the ground, there's no way those are just a graphic glitch. They are aprx. 100 meters apart and form some sort of line, five os them even a very straight one. Can somebody investigate? N: 0°10'15 E:51°13'22' HBM (talk) 15:03, 25 July 2016 (UTC)
No changes, but presumably incorrect info found.
Long story short, I have been trying to launch a sattelite into a stationary orbit, and found out that the height values in this page are actually incorrect. Keostationary orbit periapsis and apoapsis are supposed to be 2868,75 (semi-major 3468,75) but not 2863,33. When I got the correct heights exactly (possibility of error in centimeters), the map always showed Ap and Pe in the same place (they rotated with the craft :P) with the same ETA (no Kerbal Engineer, but the orbital period is exactly 6 hours), while the same didn't work for incorrect values.
Now I am too lazy and uninformed to edit the values... Sorry. But it would be great if somebody who actually wrote the
Edit: Okay, it's a bug. Resolved on it's own after some more time experimenting...
It can't be so spherical
The angular velocity of Kerbin is 0.00029157097035558 rad/s, around 4 times faster than Earth's. It should either have a weaker gravity or be very elliptical. Is it just so the physics are more simple? Are there any mods that make it more realistic except RSS? AtomicBlastPony (talk) 21:05, 15 February 2017 (UTC)
- It should have 10 times the diameter, ~112.867 times the mass (only ~9.43% the density), and atmosphere scaled up 25% too. Then it would be Earth. Kerbin is 5.16 as dense as lead, 3.06 as dense as depleted uranium, 2.59 as dense as osmium. The core of the sun is only 2.56 times as dense as Kerbin, white dwarf 17098 as dense. Gravity falls off faster so pressure should, too. Neither the density nor the atmosphere really make any sense. Aru (talk) 16:24, 18 May 2017 (UTC)
Atmospheric height fix
Update! I redid the experiments. It turns out that there are two separate thresholds. Atmosphere disappears at ~68.797km, but the music and target switching don't change until 70k km. And I just did it again, again it doesn't switch until 70k. I guess the game extends the final USSA equation past it's limit to 70,000km, either that or the gap between the two really is 0. I'll remove the first part of the post, though the core of the complaint had nothing to do with right or wrong, it had to do with the terrible word choice of "DONT change it again, without debating it in here or the forums" after a single benign edit, and not bothering to open discussion.
Aru (talk) 13:32, 10 May 2017 (UTC)
- There is only one threshold for the atmosphere height and this lays at 70km. That is also the reason why the music starts at this height because it changes when it exceeds the atmosphereDepth which is at 70km if you print this value in the game.
- Olympic1 (talk) 22:03, 11 May 2017 (UTC)
- The final USSA equation, which Kerbin atmosphere is precisely based on, stops at 84,852 km Earth geopotential, which is about 68,797 km Kerbin geometric. I'm guessing they simply extended the final equation past it's limit up to 70,000 km for the sake of convenience. All of the other limits are presumably respected, as they mark the boundary altitudes between equations. Aru (talk) 18:09, 14 May 2017 (UTC)
